14255411044 has 18 divisors (see below), whose sum is σ = 29019944310. Its totient is φ = 6109461792.

The previous prime is 14255411033. The next prime is 14255411059. The reversal of 14255411044 is 44011455241.

It can be written as a sum of positive squares in only one way, i.e., 11297138944 + 2958272100 = 106288^2 + 54390^2 .

It is a super-3 number, since 3×14255411044³ (a number of 31 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14255410997 and 14255411015.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 36365649 + ... + 36366040.

Almost surely, 2^14255411044 is an apocalyptic number.

14255411044 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

14255411044 is an abundant number, since it is smaller than the sum of its proper divisors (14764533266).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14255411044 is a wasteful number, since it uses less digits than its factorization.

14255411044 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72731707 (or 72731698 counting only the distinct ones).

The product of its (nonzero) digits is 12800, while the sum is 31.

Adding to 14255411044 its reverse (44011455241), we get a palindrome (58266866285).

The spelling of 14255411044 in words is "fourteen billion, two hundred fifty-five million, four hundred eleven thousand, forty-four".