Base | Representation |
---|---|
bin | 100000011010011100101110… |
… | …001011100101101101001111 |
3 | 200200202010110110001210112020 |
4 | 200122130232023211231033 |
5 | 122141110202240432003 |
6 | 1223104513443341223 |
7 | 42012155433430332 |
oct | 4032345613455517 |
9 | 620663413053466 |
10 | 142555034311503 |
11 | 414712835152a0 |
12 | 13ba4154681813 |
13 | 6170b60b456a8 |
14 | 272b9b4164619 |
15 | 11732b4924d53 |
hex | 81a72e2e5b4f |
142555034311503 has 8 divisors (see below), whose sum is σ = 207352777180416. Its totient is φ = 86396990491800.
The previous prime is 142555034311493. The next prime is 142555034311531. The reversal of 142555034311503 is 305113430555241.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 142555034311503 - 28 = 142555034311247 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (142555034312503) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2159924762263 + ... + 2159924762328.
It is an arithmetic number, because the mean of its divisors is an integer number (25919097147552).
Almost surely, 2142555034311503 is an apocalyptic number.
142555034311503 is a deficient number, since it is larger than the sum of its proper divisors (64797742868913).
142555034311503 is a wasteful number, since it uses less digits than its factorization.
142555034311503 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4319849524605.
The product of its (nonzero) digits is 540000, while the sum is 42.
Adding to 142555034311503 its reverse (305113430555241), we get a palindrome (447668464866744).
The spelling of 142555034311503 in words is "one hundred forty-two trillion, five hundred fifty-five billion, thirty-four million, three hundred eleven thousand, five hundred three".
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