Base | Representation |
---|---|
bin | 10100101111101010000… |
… | …100000011010010111001 |
3 | 12001021121210201111110102 |
4 | 110233222010003102321 |
5 | 141324022120334333 |
6 | 3010521013525145 |
7 | 204664506315542 |
oct | 24575204032271 |
9 | 5037553644412 |
10 | 1425561105593 |
11 | 4aa639097249 |
12 | 1b03496437b5 |
13 | a457846b721 |
14 | 4cdd72d34c9 |
15 | 2713721aae8 |
hex | 14bea1034b9 |
1425561105593 has 4 divisors (see below), whose sum is σ = 1458713689488. Its totient is φ = 1392408521700.
The previous prime is 1425561105539. The next prime is 1425561105643. The reversal of 1425561105593 is 3955011655241.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1425561105593 - 218 = 1425560843449 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1425561105893) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16576291883 + ... + 16576291968.
It is an arithmetic number, because the mean of its divisors is an integer number (364678422372).
Almost surely, 21425561105593 is an apocalyptic number.
It is an amenable number.
1425561105593 is a deficient number, since it is larger than the sum of its proper divisors (33152583895).
1425561105593 is an equidigital number, since it uses as much as digits as its factorization.
1425561105593 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 33152583894.
The product of its (nonzero) digits is 810000, while the sum is 47.
The spelling of 1425561105593 in words is "one trillion, four hundred twenty-five billion, five hundred sixty-one million, one hundred five thousand, five hundred ninety-three".
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