Base | Representation |
---|---|
bin | 10100110000001011011… |
… | …101000111001001101001 |
3 | 12001100001211212111102110 |
4 | 110300023131013021221 |
5 | 141331144024314423 |
6 | 3011052345152533 |
7 | 205014421144014 |
oct | 24601335071151 |
9 | 5040054774373 |
10 | 1426121323113 |
11 | 4aa8a6342a33 |
12 | 1b048518b749 |
13 | a4637548796 |
14 | 4d04b88237b |
15 | 2716b4cb193 |
hex | 14c0b747269 |
1426121323113 has 16 divisors (see below), whose sum is σ = 1925943776000. Its totient is φ = 938527948800.
The previous prime is 1426121323051. The next prime is 1426121323163. The reversal of 1426121323113 is 3113231216241.
It is not a de Polignac number, because 1426121323113 - 26 = 1426121323049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1426121323163) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 619113 + ... + 1798761.
It is an arithmetic number, because the mean of its divisors is an integer number (120371486000).
Almost surely, 21426121323113 is an apocalyptic number.
It is an amenable number.
1426121323113 is a deficient number, since it is larger than the sum of its proper divisors (499822452887).
1426121323113 is a wasteful number, since it uses less digits than its factorization.
1426121323113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1184832.
The product of its digits is 5184, while the sum is 30.
Adding to 1426121323113 its reverse (3113231216241), we get a palindrome (4539352539354).
The spelling of 1426121323113 in words is "one trillion, four hundred twenty-six billion, one hundred twenty-one million, three hundred twenty-three thousand, one hundred thirteen".
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