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142631125601 = 236201353287
BaseRepresentation
bin1000010011010101111…
…0100100001001100001
3111122011012121220112112
42010311132210021201
54314102032004401
6145305052005105
713206350364266
oct2046536441141
9448135556475
10142631125601
1155542608808
1223786a60795
13105b0a12353
146c90c5326d
153a9bbee3bb
hex21357a4261

142631125601 has 4 divisors (see below), whose sum is σ = 148832478912. Its totient is φ = 136429772292.

The previous prime is 142631125597. The next prime is 142631125607. The reversal of 142631125601 is 106521136241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 142631125601 - 22 = 142631125597 is a prime.

It is a super-2 number, since 2×1426311256012 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (142631125607) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3100676621 + ... + 3100676666.

It is an arithmetic number, because the mean of its divisors is an integer number (37208119728).

Almost surely, 2142631125601 is an apocalyptic number.

It is an amenable number.

142631125601 is a deficient number, since it is larger than the sum of its proper divisors (6201353311).

142631125601 is an equidigital number, since it uses as much as digits as its factorization.

142631125601 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6201353310.

The product of its (nonzero) digits is 8640, while the sum is 32.

The spelling of 142631125601 in words is "one hundred forty-two billion, six hundred thirty-one million, one hundred twenty-five thousand, six hundred one".

Divisors: 1 23 6201353287 142631125601