Base | Representation |
---|---|
bin | 10100110000100101001… |
… | …111011000011110111001 |
3 | 12001101011222220021211220 |
4 | 110300211033120132321 |
5 | 141333040301303310 |
6 | 3011203321342253 |
7 | 205031223230400 |
oct | 24604517303671 |
9 | 5041158807756 |
10 | 1426553931705 |
11 | 4aaaa85601a1 |
12 | 1b0586037989 |
13 | a46a60664b6 |
14 | 4d08d0d4637 |
15 | 27194481670 |
hex | 14c253d87b9 |
1426553931705 has 24 divisors (see below), whose sum is σ = 2655137115072. Its totient is φ = 652138939872.
The previous prime is 1426553931697. The next prime is 1426553931721. The reversal of 1426553931705 is 5071393556241.
It is not a de Polignac number, because 1426553931705 - 23 = 1426553931697 is a prime.
It is a super-2 number, since 2×14265539317052 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 970444117 + ... + 970445586.
It is an arithmetic number, because the mean of its divisors is an integer number (110630713128).
Almost surely, 21426553931705 is an apocalyptic number.
1426553931705 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1426553931705 is a deficient number, since it is larger than the sum of its proper divisors (1228583183367).
1426553931705 is a wasteful number, since it uses less digits than its factorization.
1426553931705 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1940889725 (or 1940889718 counting only the distinct ones).
The product of its (nonzero) digits is 3402000, while the sum is 51.
The spelling of 1426553931705 in words is "one trillion, four hundred twenty-six billion, five hundred fifty-three million, nine hundred thirty-one thousand, seven hundred five".
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