14289980276453 has 4 divisors (see below), whose sum is σ = 16331406030240. Its totient is φ = 12248554522668.

The previous prime is 14289980276449. The next prime is 14289980276491. The reversal of 14289980276453 is 35467208998241.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14289980276453 - 2² = 14289980276449 is a prime.

It is a super-2 number, since 2×14289980276453² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14289980276053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1020712876883 + ... + 1020712876896.

It is an arithmetic number, because the mean of its divisors is an integer number (4082851507560).

It is a 1-persistent number, because it is pandigital, but 2⋅14289980276453 = 28579960552906 is not.

Almost surely, 2^{14289980276453} is an apocalyptic number.

It is an amenable number.

14289980276453 is a deficient number, since it is larger than the sum of its proper divisors (2041425753787).

14289980276453 is an equidigital number, since it uses as much as digits as its factorization.

14289980276453 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2041425753786.

The product of its (nonzero) digits is 209018880, while the sum is 68.

The spelling of 14289980276453 in words is "fourteen trillion, two hundred eighty-nine billion, nine hundred eighty million, two hundred seventy-six thousand, four hundred fifty-three".