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143003200042 = 271501600021
BaseRepresentation
bin1000010100101110100…
…1111010101000101010
3111200010010202020201101
42011023221322220222
54320332304400132
6145410022512014
713221516100363
oct2051351725052
9450103666641
10143003200042
115571363a84a
122386b59560a
131063cb26c41
146cc8428b6a
153abe6e87e7
hex214ba7aa2a

143003200042 has 4 divisors (see below), whose sum is σ = 214504800066. Its totient is φ = 71501600020.

The previous prime is 143003200037. The next prime is 143003200057. The reversal of 143003200042 is 240002300341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 142967928321 + 35271721 = 378111^2 + 5939^2 .

It is a junction number, because it is equal to n+sod(n) for n = 143003199992 and 143003200019.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35750800009 + ... + 35750800012.

Almost surely, 2143003200042 is an apocalyptic number.

143003200042 is a deficient number, since it is larger than the sum of its proper divisors (71501600024).

143003200042 is an equidigital number, since it uses as much as digits as its factorization.

143003200042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 71501600023.

The product of its (nonzero) digits is 576, while the sum is 19.

Adding to 143003200042 its reverse (240002300341), we get a palindrome (383005500383).

The spelling of 143003200042 in words is "one hundred forty-three billion, three million, two hundred thousand, forty-two".

Divisors: 1 2 71501600021 143003200042