Base | Representation |
---|---|
bin | 100000100000111110010101… |
… | …010111101101010011110011 |
3 | 200202022222212202111122222220 |
4 | 200200332111113231103303 |
5 | 122220432022141443103 |
6 | 1224050512511332123 |
7 | 42056441415202005 |
oct | 4040762527552363 |
9 | 622288782448886 |
10 | 143003442140403 |
11 | 41624467aa5a59 |
12 | 14057037521043 |
13 | 61a42223cc270 |
14 | 2745591400375 |
15 | 117ecab00dc53 |
hex | 820f955ed4f3 |
143003442140403 has 32 divisors (see below), whose sum is σ = 208971398748672. Its totient is φ = 86453887430400.
The previous prime is 143003442140333. The next prime is 143003442140417. The reversal of 143003442140403 is 304041244300341.
It is not a de Polignac number, because 143003442140403 - 28 = 143003442140147 is a prime.
It is not an unprimeable number, because it can be changed into a prime (143003442140443) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 91115925 + ... + 92672102.
It is an arithmetic number, because the mean of its divisors is an integer number (6530356210896).
Almost surely, 2143003442140403 is an apocalyptic number.
143003442140403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
143003442140403 is a deficient number, since it is larger than the sum of its proper divisors (65967956608269).
143003442140403 is a wasteful number, since it uses less digits than its factorization.
143003442140403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 183788395.
The product of its (nonzero) digits is 55296, while the sum is 33.
Adding to 143003442140403 its reverse (304041244300341), we get a palindrome (447044686440744).
The spelling of 143003442140403 in words is "one hundred forty-three trillion, three billion, four hundred forty-two million, one hundred forty thousand, four hundred three".
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