14301003117 has 4 divisors (see below), whose sum is σ = 19068004160. Its totient is φ = 9534002076.

The previous prime is 14301003113. The next prime is 14301003121. The reversal of 14301003117 is 71130010341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (14301003113) and next prime (14301003121).

It is not a de Polignac number, because 14301003117 - 2² = 14301003113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14301003093 and 14301003102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14301003113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2383500517 + ... + 2383500522.

It is an arithmetic number, because the mean of its divisors is an integer number (4767001040).

Almost surely, 2^14301003117 is an apocalyptic number.

It is an amenable number.

14301003117 is a deficient number, since it is larger than the sum of its proper divisors (4767001043).

14301003117 is an equidigital number, since it uses as much as digits as its factorization.

14301003117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4767001042.

The product of its (nonzero) digits is 252, while the sum is 21.

Adding to 14301003117 its reverse (71130010341), we get a palindrome (85431013458).

The spelling of 14301003117 in words is "fourteen billion, three hundred one million, three thousand, one hundred seventeen".