Base | Representation |
---|---|
bin | 10100110011111010111… |
… | …111101001100011100011 |
3 | 12001201102220222010012120 |
4 | 110303322333221203203 |
5 | 141412411333202210 |
6 | 3012555230155323 |
7 | 205216130354502 |
oct | 24637277514343 |
9 | 5051386863176 |
10 | 1430140131555 |
11 | 501578903223 |
12 | 1b1207052b43 |
13 | a4b28024145 |
14 | 4d30d4d0839 |
15 | 27304219270 |
hex | 14cfafe98e3 |
1430140131555 has 8 divisors (see below), whose sum is σ = 2288224210512. Its totient is φ = 762741403488.
The previous prime is 1430140131527. The next prime is 1430140131569. The reversal of 1430140131555 is 5551310410341.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1430140131555 - 25 = 1430140131523 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 47671337704 + ... + 47671337733.
It is an arithmetic number, because the mean of its divisors is an integer number (286028026314).
Almost surely, 21430140131555 is an apocalyptic number.
1430140131555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1430140131555 is a deficient number, since it is larger than the sum of its proper divisors (858084078957).
1430140131555 is an equidigital number, since it uses as much as digits as its factorization.
1430140131555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 95342675445.
The product of its (nonzero) digits is 18000, while the sum is 33.
Adding to 1430140131555 its reverse (5551310410341), we get a palindrome (6981450541896).
The spelling of 1430140131555 in words is "one trillion, four hundred thirty billion, one hundred forty million, one hundred thirty-one thousand, five hundred fifty-five".
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