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143020404343 = 1039113763873
BaseRepresentation
bin1000010100110010101…
…1100010111001110111
3111200011100010022120201
42011030223202321313
54320401210414333
6145411435341331
713222115243605
oct2051453427167
9450140108521
10143020404343
1155722320683
12238752b1847
131064356b9bb
146cca826875
153ac0e9617d
hex214cae2e77

143020404343 has 4 divisors (see below), whose sum is σ = 143034178608. Its totient is φ = 143006630080.

The previous prime is 143020404323. The next prime is 143020404347. The reversal of 143020404343 is 343404020341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 343404020341 = 641535731701.

It is a cyclic number.

It is not a de Polignac number, because 143020404343 - 217 = 143020273271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143020404347) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6871546 + ... + 6892327.

It is an arithmetic number, because the mean of its divisors is an integer number (35758544652).

Almost surely, 2143020404343 is an apocalyptic number.

143020404343 is a deficient number, since it is larger than the sum of its proper divisors (13774265).

143020404343 is a wasteful number, since it uses less digits than its factorization.

143020404343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13774264.

The product of its (nonzero) digits is 13824, while the sum is 28.

Adding to 143020404343 its reverse (343404020341), we get a palindrome (486424424684).

The spelling of 143020404343 in words is "one hundred forty-three billion, twenty million, four hundred four thousand, three hundred forty-three".

Divisors: 1 10391 13763873 143020404343