14302111400042 has 4 divisors (see below), whose sum is σ = 21453167100066. Its totient is φ = 7151055700020.

The previous prime is 14302111400009. The next prime is 14302111400089. The reversal of 14302111400042 is 24000411120341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 14302003676401 + 107723641 = 3781799^2 + 10379^2 .

It is a super-2 number, since 2×14302111400042² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14302111399990 and 14302111400017.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3575527850009 + ... + 3575527850012.

Almost surely, 2^{14302111400042} is an apocalyptic number.

14302111400042 is a deficient number, since it is larger than the sum of its proper divisors (7151055700024).

14302111400042 is an equidigital number, since it uses as much as digits as its factorization.

14302111400042 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7151055700023.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14302111400042 its reverse (24000411120341), we get a palindrome (38302522520383).

The spelling of 14302111400042 in words is "fourteen trillion, three hundred two billion, one hundred eleven million, four hundred thousand, forty-two".