Base | Representation |
---|---|
bin | 10100110011111111001… |
… | …110110110111000010001 |
3 | 12001201121212202011000212 |
4 | 110303333032312320101 |
5 | 141413033033232103 |
6 | 3013010250053505 |
7 | 205220652563342 |
oct | 24637716667021 |
9 | 5051555664025 |
10 | 1430211227153 |
11 | 501604a52415 |
12 | 1b1226a1a295 |
13 | a4b39987547 |
14 | 4d318b1a0c9 |
15 | 2730a5ae7d8 |
hex | 14cff3b6e11 |
1430211227153 has 8 divisors (see below), whose sum is σ = 1432484440128. Its totient is φ = 1427938208944.
The previous prime is 1430211227149. The next prime is 1430211227197. The reversal of 1430211227153 is 3517221120341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1430211227153 - 22 = 1430211227149 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1430211227453) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 23917550 + ... + 23977272.
It is an arithmetic number, because the mean of its divisors is an integer number (179060555016).
Almost surely, 21430211227153 is an apocalyptic number.
It is an amenable number.
1430211227153 is a deficient number, since it is larger than the sum of its proper divisors (2273212975).
1430211227153 is an equidigital number, since it uses as much as digits as its factorization.
1430211227153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 97383.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 1430211227153 its reverse (3517221120341), we get a palindrome (4947432347494).
The spelling of 1430211227153 in words is "one trillion, four hundred thirty billion, two hundred eleven million, two hundred twenty-seven thousand, one hundred fifty-three".
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