Base | Representation |
---|---|
bin | 10100110100000000000… |
… | …000000111111010110001 |
3 | 12001201122210001021212120 |
4 | 110310000000013322301 |
5 | 141413044340021001 |
6 | 3013011430544453 |
7 | 205221200423064 |
oct | 24640000077261 |
9 | 5051583037776 |
10 | 1430224142001 |
11 | 501611273546 |
12 | 1b122b208129 |
13 | a4b3c559a75 |
14 | 4d31a71c8db |
15 | 2730b7b1236 |
hex | 14d00007eb1 |
1430224142001 has 8 divisors (see below), whose sum is σ = 1906973410944. Its totient is φ = 953478817200.
The previous prime is 1430224141993. The next prime is 1430224142021. The reversal of 1430224142001 is 1002414220341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1430224142001 - 23 = 1430224141993 is a prime.
It is a super-2 number, since 2×14302241420012 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1430224142021) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1320 + ... + 1691286.
It is an arithmetic number, because the mean of its divisors is an integer number (238371676368).
Almost surely, 21430224142001 is an apocalyptic number.
It is an amenable number.
1430224142001 is a deficient number, since it is larger than the sum of its proper divisors (476749268943).
1430224142001 is a wasteful number, since it uses less digits than its factorization.
1430224142001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1972071.
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 1430224142001 its reverse (1002414220341), we get a palindrome (2432638362342).
The spelling of 1430224142001 in words is "one trillion, four hundred thirty billion, two hundred twenty-four million, one hundred forty-two thousand, one".
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