Base | Representation |
---|---|
bin | 10100110100000100101… |
… | …010010110100111101011 |
3 | 12001201212020011012110220 |
4 | 110310010222112213223 |
5 | 141413224343234011 |
6 | 3013023302341123 |
7 | 205223140063425 |
oct | 24640452264753 |
9 | 5051766135426 |
10 | 1430302321131 |
11 | 5016514106a2 |
12 | 1b125142a7a3 |
13 | a4b528003c8 |
14 | 4d326c6d815 |
15 | 273135a5506 |
hex | 14d04a969eb |
1430302321131 has 8 divisors (see below), whose sum is σ = 1908584516160. Its totient is φ = 952777503432.
The previous prime is 1430302321117. The next prime is 1430302321141. The reversal of 1430302321131 is 1311232030341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1430302321131 - 210 = 1430302320107 is a prime.
It is a super-2 number, since 2×14303023211312 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1430302321141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 189339925 + ... + 189347478.
It is an arithmetic number, because the mean of its divisors is an integer number (238573064520).
Almost surely, 21430302321131 is an apocalyptic number.
1430302321131 is a deficient number, since it is larger than the sum of its proper divisors (478282195029).
1430302321131 is a wasteful number, since it uses less digits than its factorization.
1430302321131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 378688665.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 1430302321131 its reverse (1311232030341), we get a palindrome (2741534351472).
The spelling of 1430302321131 in words is "one trillion, four hundred thirty billion, three hundred two million, three hundred twenty-one thousand, one hundred thirty-one".
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