Search a number
-
+
143030557 = 157990583
BaseRepresentation
bin10001000011001…
…11100100011101
3100222010201001001
420201213210131
5243103434212
622105350301
73354511465
oct1041474435
9328121031
10143030557
1173811a7a
123ba98391
132382b887
1414dd2ba5
15c854657
hex886791d

143030557 has 4 divisors (see below), whose sum is σ = 143122720. Its totient is φ = 142938396.

The previous prime is 143030533. The next prime is 143030561. The reversal of 143030557 is 755030341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143030557 - 27 = 143030429 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143030507) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43713 + ... + 46870.

It is an arithmetic number, because the mean of its divisors is an integer number (35780680).

Almost surely, 2143030557 is an apocalyptic number.

It is an amenable number.

143030557 is a deficient number, since it is larger than the sum of its proper divisors (92163).

143030557 is an equidigital number, since it uses as much as digits as its factorization.

143030557 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 92162.

The product of its (nonzero) digits is 6300, while the sum is 28.

The square root of 143030557 is about 11959.5383272098. The cubic root of 143030557 is about 522.9693981634.

Adding to 143030557 its reverse (755030341), we get a palindrome (898060898).

The spelling of 143030557 in words is "one hundred forty-three million, thirty thousand, five hundred fifty-seven".

Divisors: 1 1579 90583 143030557