14303233117045 has 4 divisors (see below), whose sum is σ = 17163879740460. Its totient is φ = 11442586493632.

The previous prime is 14303233116989. The next prime is 14303233117051. The reversal of 14303233117045 is 54071133230341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7876369281169 + 6426863835876 = 2806487^2 + 2535126^2 .

It is a cyclic number.

It is not a de Polignac number, because 14303233117045 - 2⁹ = 14303233116533 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14303233116995 and 14303233117013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1430323311700 + ... + 1430323311709.

It is an arithmetic number, because the mean of its divisors is an integer number (4290969935115).

Almost surely, 2^{14303233117045} is an apocalyptic number.

It is an amenable number.

14303233117045 is a deficient number, since it is larger than the sum of its proper divisors (2860646623415).

14303233117045 is an equidigital number, since it uses as much as digits as its factorization.

14303233117045 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2860646623414.

The product of its (nonzero) digits is 90720, while the sum is 37.

Adding to 14303233117045 its reverse (54071133230341), we get a palindrome (68374366347386).

The spelling of 14303233117045 in words is "fourteen trillion, three hundred three billion, two hundred thirty-three million, one hundred seventeen thousand, forty-five".