1430323441431 has 8 divisors (see below), whose sum is σ = 1907317947120. Its totient is φ = 953438948352.

The previous prime is 1430323441411. The next prime is 1430323441447. The reversal of 1430323441431 is 1341443230341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1430323441431 - 2¹³ = 1430323433239 is a prime.

It is a super-2 number, since 2×1430323441431² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1430323441392 and 1430323441401.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1430323441411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27472810 + ... + 27524823.

It is an arithmetic number, because the mean of its divisors is an integer number (238414743390).

Almost surely, 2^{1430323441431} is an apocalyptic number.

1430323441431 is a deficient number, since it is larger than the sum of its proper divisors (476994505689).

1430323441431 is an equidigital number, since it uses as much as digits as its factorization.

1430323441431 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55006305.

The product of its (nonzero) digits is 41472, while the sum is 33.

Adding to 1430323441431 its reverse (1341443230341), we get a palindrome (2771766671772).

The spelling of 1430323441431 in words is "one trillion, four hundred thirty billion, three hundred twenty-three million, four hundred forty-one thousand, four hundred thirty-one".