Base | Representation |
---|---|
bin | 1101000000100100011101… |
… | …1110110011110001100010 |
3 | 1212122101200100111002112001 |
4 | 3100021013132303301202 |
5 | 3333321421212320102 |
6 | 50230524302554214 |
7 | 3004250404662613 |
oct | 320110736636142 |
9 | 55571610432461 |
10 | 14303440354402 |
11 | 4615067210091 |
12 | 173012929896a |
13 | 7c9a68767604 |
14 | 37640c483c0a |
15 | 19c0ea636487 |
hex | d02477b3c62 |
14303440354402 has 4 divisors (see below), whose sum is σ = 21455160531606. Its totient is φ = 7151720177200.
The previous prime is 14303440354393. The next prime is 14303440354417. The reversal of 14303440354402 is 20445304430341.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 10224652155201 + 4078788199201 = 3197601^2 + 2019601^2 .
It is a super-2 number, since 2×143034403544022 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3575860088599 + ... + 3575860088602.
Almost surely, 214303440354402 is an apocalyptic number.
14303440354402 is a deficient number, since it is larger than the sum of its proper divisors (7151720177204).
14303440354402 is an equidigital number, since it uses as much as digits as its factorization.
14303440354402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7151720177203.
The product of its (nonzero) digits is 276480, while the sum is 37.
Adding to 14303440354402 its reverse (20445304430341), we get a palindrome (34748744784743).
The spelling of 14303440354402 in words is "fourteen trillion, three hundred three billion, four hundred forty million, three hundred fifty-four thousand, four hundred two".
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