14310000211 has 4 divisors (see below), whose sum is σ = 15410769472. Its totient is φ = 13209230952.

The previous prime is 14310000193. The next prime is 14310000227. The reversal of 14310000211 is 11200001341.

14310000211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14310000211 - 2¹⁹ = 14309475923 is a prime.

It is a super-2 number, since 2×14310000211² (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (13), and also a Moran number because the ratio is a prime number: 1100769247 = 14310000211 / (1 + 4 + 3 + 1 + 0 + 0 + 0 + 0 + 2 + 1 + 1).

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14310000191 and 14310000200.

It is not an unprimeable number, because it can be changed into a prime (14310000281) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550384611 + ... + 550384636.

It is an arithmetic number, because the mean of its divisors is an integer number (3852692368).

Almost surely, 2^14310000211 is an apocalyptic number.

14310000211 is a deficient number, since it is larger than the sum of its proper divisors (1100769261).

14310000211 is a wasteful number, since it uses less digits than its factorization.

14310000211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1100769260.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14310000211 its reverse (11200001341), we get a palindrome (25510001552).

The spelling of 14310000211 in words is "fourteen billion, three hundred ten million, two hundred eleven", and thus it is an aban number.