Base | Representation |
---|---|
bin | 11010101001111000… |
… | …11110001101111011 |
3 | 1100221021212101002220 |
4 | 31110330132031323 |
5 | 213301332243233 |
6 | 10323545455123 |
7 | 1014421223346 |
oct | 152474361573 |
9 | 40837771086 |
10 | 14310040443 |
11 | 6083710206 |
12 | 29344a14a3 |
13 | 1470913a6a |
14 | 99a74145d |
15 | 58b476eb3 |
hex | 354f1e37b |
14310040443 has 4 divisors (see below), whose sum is σ = 19080053928. Its totient is φ = 9540026960.
The previous prime is 14310040429. The next prime is 14310040453. The reversal of 14310040443 is 34404001341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14310040443 - 225 = 14276486011 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14310040453) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385006738 + ... + 2385006743.
It is an arithmetic number, because the mean of its divisors is an integer number (4770013482).
Almost surely, 214310040443 is an apocalyptic number.
14310040443 is a deficient number, since it is larger than the sum of its proper divisors (4770013485).
14310040443 is an equidigital number, since it uses as much as digits as its factorization.
14310040443 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4770013484.
The product of its (nonzero) digits is 2304, while the sum is 24.
Adding to 14310040443 its reverse (34404001341), we get a palindrome (48714041784).
The spelling of 14310040443 in words is "fourteen billion, three hundred ten million, forty thousand, four hundred forty-three".
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