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1431011040000 = 28354171571117
BaseRepresentation
bin10100110100101110111…
…001111001101100000000
312001210200121201211222220
4110310232321321230000
5141421202311240000
63013221500531040
7205246534100253
oct24645671715400
95053617654886
101431011040000
11501985475673
121b140a850a80
13a4c365a3199
144d39303709a
15273558eb1a0
hex14d2ee79b00

1431011040000 has 720 divisors, whose sum is σ = 5075786203488. Its totient is φ = 356548608000.

The previous prime is 1431011039999. The next prime is 1431011040077. The reversal of 1431011040000 is 401101341.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 1281119442 + ... + 1281120558.

Almost surely, 21431011040000 is an apocalyptic number.

1431011040000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1431011040000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2537893101744).

1431011040000 is an abundant number, since it is smaller than the sum of its proper divisors (3644775163488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431011040000 is a wasteful number, since it uses less digits than its factorization.

1431011040000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1330 (or 1301 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 1431011040000 its reverse (401101341), we get a palindrome (1431412141341).

The spelling of 1431011040000 in words is "one trillion, four hundred thirty-one billion, eleven million, forty thousand".