14310120106055 has 4 divisors (see below), whose sum is σ = 17172144127272. Its totient is φ = 11448096084840.

The previous prime is 14310120105979. The next prime is 14310120106111. The reversal of 14310120106055 is 55060102101341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 14310120106055 - 2¹⁸ = 14310119843911 is a prime.

It is a super-3 number, since 3×14310120106055³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1431012010601 + ... + 1431012010610.

It is an arithmetic number, because the mean of its divisors is an integer number (4293036031818).

Almost surely, 2^{14310120106055} is an apocalyptic number.

14310120106055 is a deficient number, since it is larger than the sum of its proper divisors (2862024021217).

14310120106055 is an equidigital number, since it uses as much as digits as its factorization.

14310120106055 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2862024021216.

The product of its (nonzero) digits is 3600, while the sum is 29.

Adding to 14310120106055 its reverse (55060102101341), we get a palindrome (69370222207396).

The spelling of 14310120106055 in words is "fourteen trillion, three hundred ten billion, one hundred twenty million, one hundred six thousand, fifty-five".