Base | Representation |
---|---|
bin | 1101000000111101010111… |
… | …0011001111000110110011 |
3 | 1212200000221002010202102121 |
4 | 3100033111303033012303 |
5 | 3333424112444304303 |
6 | 50233551344055111 |
7 | 3004605121613533 |
oct | 320172563170663 |
9 | 55600832122377 |
10 | 14310123041203 |
11 | 4617986435640 |
12 | 1731493304497 |
13 | 7ca5920c0262 |
14 | 376883c014c3 |
15 | 19c38c1719bd |
hex | d03d5ccf1b3 |
14310123041203 has 8 divisors (see below), whose sum is σ = 16289784331776. Its totient is φ = 12443585253000.
The previous prime is 14310123041029. The next prime is 14310123041239. The reversal of 14310123041203 is 30214032101341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 14310123041203 - 229 = 14309586170291 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14310123041003) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 28280875323 + ... + 28280875828.
It is an arithmetic number, because the mean of its divisors is an integer number (2036223041472).
Almost surely, 214310123041203 is an apocalyptic number.
14310123041203 is a deficient number, since it is larger than the sum of its proper divisors (1979661290573).
14310123041203 is a wasteful number, since it uses less digits than its factorization.
14310123041203 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 56561751185.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 14310123041203 its reverse (30214032101341), we get a palindrome (44524155142544).
The spelling of 14310123041203 in words is "fourteen trillion, three hundred ten billion, one hundred twenty-three million, forty-one thousand, two hundred three".
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