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14310202304041 = 79633121221773
BaseRepresentation
bin1101000000111101101010…
…0001100110011000101001
31212200001010121021201121021
43100033122201212120221
53333424243242212131
650234003255012441
73004610103416530
oct320173241463051
955601117251537
1014310202304041
114617a17152a16
1217314b596a121
137ca5a5652c47
14376890555317
1519c3940cbe11
hexd03da866629

14310202304041 has 8 divisors (see below), whose sum is σ = 16354687463744. Its totient is φ = 12265759780560.

The previous prime is 14310202304029. The next prime is 14310202304087. The reversal of 14310202304041 is 14040320201341.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14310202304041 - 221 = 14310200206889 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14310202303997 and 14310202304015.

It is not an unprimeable number, because it can be changed into a prime (14310202304141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9936570 + ... + 11285203.

It is an arithmetic number, because the mean of its divisors is an integer number (2044335932968).

Almost surely, 214310202304041 is an apocalyptic number.

It is an amenable number.

14310202304041 is a deficient number, since it is larger than the sum of its proper divisors (2044485159703).

14310202304041 is an equidigital number, since it uses as much as digits as its factorization.

14310202304041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21318111.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 14310202304041 its reverse (14040320201341), we get a palindrome (28350522505382).

The spelling of 14310202304041 in words is "fourteen trillion, three hundred ten billion, two hundred two million, three hundred four thousand, forty-one".

Divisors: 1 7 96331 674317 21221773 148552411 2044314614863 14310202304041