Base | Representation |
---|---|
bin | 1101000000111101101010… |
… | …0001100110011000101001 |
3 | 1212200001010121021201121021 |
4 | 3100033122201212120221 |
5 | 3333424243242212131 |
6 | 50234003255012441 |
7 | 3004610103416530 |
oct | 320173241463051 |
9 | 55601117251537 |
10 | 14310202304041 |
11 | 4617a17152a16 |
12 | 17314b596a121 |
13 | 7ca5a5652c47 |
14 | 376890555317 |
15 | 19c3940cbe11 |
hex | d03da866629 |
14310202304041 has 8 divisors (see below), whose sum is σ = 16354687463744. Its totient is φ = 12265759780560.
The previous prime is 14310202304029. The next prime is 14310202304087. The reversal of 14310202304041 is 14040320201341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14310202304041 - 221 = 14310200206889 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14310202303997 and 14310202304015.
It is not an unprimeable number, because it can be changed into a prime (14310202304141) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9936570 + ... + 11285203.
It is an arithmetic number, because the mean of its divisors is an integer number (2044335932968).
Almost surely, 214310202304041 is an apocalyptic number.
It is an amenable number.
14310202304041 is a deficient number, since it is larger than the sum of its proper divisors (2044485159703).
14310202304041 is an equidigital number, since it uses as much as digits as its factorization.
14310202304041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21318111.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 14310202304041 its reverse (14040320201341), we get a palindrome (28350522505382).
The spelling of 14310202304041 in words is "fourteen trillion, three hundred ten billion, two hundred two million, three hundred four thousand, forty-one".
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