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1431020323111 = 9277154254643
BaseRepresentation
bin10100110100101111011…
…101010100000100100111
312001210201021012111000211
4110310233131110010213
5141421212200314421
63013222431520251
7205250006022601
oct24645735240447
95053637174024
101431020323111
1150198a736165
121b1411989087
13a4c384a3652
144d394372171
15273566319e1
hex14d2f754127

1431020323111 has 4 divisors (see below), whose sum is σ = 1431174587032. Its totient is φ = 1430866059192.

The previous prime is 1431020323097. The next prime is 1431020323163. The reversal of 1431020323111 is 1113230201341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1431020323111 - 25 = 1431020323079 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431020333111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 77118045 + ... + 77136598.

It is an arithmetic number, because the mean of its divisors is an integer number (357793646758).

Almost surely, 21431020323111 is an apocalyptic number.

1431020323111 is a deficient number, since it is larger than the sum of its proper divisors (154263921).

1431020323111 is an equidigital number, since it uses as much as digits as its factorization.

1431020323111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 154263920.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 1431020323111 its reverse (1113230201341), we get a palindrome (2544250524452).

The spelling of 1431020323111 in words is "one trillion, four hundred thirty-one billion, twenty million, three hundred twenty-three thousand, one hundred eleven".

Divisors: 1 9277 154254643 1431020323111