143102121231 has 4 divisors (see below), whose sum is σ = 190802828312. Its totient is φ = 95401414152.

The previous prime is 143102121181. The next prime is 143102121251. The reversal of 143102121231 is 132121201341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143102121231 - 2¹⁵ = 143102088463 is a prime.

It is a super-2 number, since 2×143102121231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143102121198 and 143102121207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143102121251) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23850353536 + ... + 23850353541.

It is an arithmetic number, because the mean of its divisors is an integer number (47700707078).

Almost surely, 2^143102121231 is an apocalyptic number.

143102121231 is a deficient number, since it is larger than the sum of its proper divisors (47700707081).

143102121231 is an equidigital number, since it uses as much as digits as its factorization.

143102121231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47700707080.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 143102121231 its reverse (132121201341), we get a palindrome (275223322572).

The spelling of 143102121231 in words is "one hundred forty-three billion, one hundred two million, one hundred twenty-one thousand, two hundred thirty-one".