143104012141 has 4 divisors (see below), whose sum is σ = 143104924800. Its totient is φ = 143103099484.

The previous prime is 143104012127. The next prime is 143104012151. The reversal of 143104012141 is 141210401341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 143104012141 - 2⁷ = 143104012013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143104012151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154651 + ... + 556888.

It is an arithmetic number, because the mean of its divisors is an integer number (35776231200).

Almost surely, 2^143104012141 is an apocalyptic number.

It is an amenable number.

143104012141 is a deficient number, since it is larger than the sum of its proper divisors (912659).

143104012141 is an equidigital number, since it uses as much as digits as its factorization.

143104012141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 912658.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 143104012141 its reverse (141210401341), we get a palindrome (284314413482).

The spelling of 143104012141 in words is "one hundred forty-three billion, one hundred four million, twelve thousand, one hundred forty-one".