14310444042241 has 4 divisors (see below), whose sum is σ = 14310461913300. Its totient is φ = 14310426171184.

The previous prime is 14310444042217. The next prime is 14310444042299. The reversal of 14310444042241 is 14224044401341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4907199648400 + 9403244393841 = 2215220^2 + 3066471^2 .

It is a cyclic number.

It is not a de Polignac number, because 14310444042241 - 2³³ = 14301854107649 is a prime.

It is a super-2 number, since 2×14310444042241² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14310444042197 and 14310444042206.

It is not an unprimeable number, because it can be changed into a prime (14310444022241) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7675126 + ... + 9355663.

It is an arithmetic number, because the mean of its divisors is an integer number (3577615478325).

Almost surely, 2^{14310444042241} is an apocalyptic number.

It is an amenable number.

14310444042241 is a deficient number, since it is larger than the sum of its proper divisors (17871059).

14310444042241 is an equidigital number, since it uses as much as digits as its factorization.

14310444042241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 17871058.

The product of its (nonzero) digits is 49152, while the sum is 34.

Adding to 14310444042241 its reverse (14224044401341), we get a palindrome (28534488443582).

The spelling of 14310444042241 in words is "fourteen trillion, three hundred ten billion, four hundred forty-four million, forty-two thousand, two hundred forty-one".