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14311011111211 = 83172421820617
BaseRepresentation
bin1101000001000000101010…
…1110111101000100101011
31212200010012222012101110101
43100100022232331010223
53333432422321024321
650234215430330231
73004636124234113
oct320201256750453
955603188171411
1014311011111211
1146182a17597a1
1217316a07b9977
137ca6a409a779
14376929b34043
1519c3e00e3791
hexd040abbd12b

14311011111211 has 4 divisors (see below), whose sum is σ = 14483432931912. Its totient is φ = 14138589290512.

The previous prime is 14311011111193. The next prime is 14311011111283. The reversal of 14311011111211 is 11211111011341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14311011111211 - 25 = 14311011111179 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14311011181211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 86210910226 + ... + 86210910391.

It is an arithmetic number, because the mean of its divisors is an integer number (3620858232978).

Almost surely, 214311011111211 is an apocalyptic number.

14311011111211 is a deficient number, since it is larger than the sum of its proper divisors (172421820701).

14311011111211 is an equidigital number, since it uses as much as digits as its factorization.

14311011111211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 172421820700.

The product of its (nonzero) digits is 24, while the sum is 19.

Adding to 14311011111211 its reverse (11211111011341), we get a palindrome (25522122122552).

The spelling of 14311011111211 in words is "fourteen trillion, three hundred eleven billion, eleven million, one hundred eleven thousand, two hundred eleven".

Divisors: 1 83 172421820617 14311011111211