1431112124133 has 6 divisors (see below), whose sum is σ = 2067161957094. Its totient is φ = 954074749416.

The previous prime is 1431112124131. The next prime is 1431112124149. The reversal of 1431112124133 is 3314212111341.

1431112124133 is a `hidden beast` number, since 1 + 4 + 31 + 1 + 1 + 212 + 413 + 3 = 666.

It can be written as a sum of positive squares in only one way, i.e., 895402310049 + 535709814084 = 946257^2 + 731922^2 .

It is not a de Polignac number, because 1431112124133 - 2¹ = 1431112124131 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1431112124097 and 1431112124106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431112124131) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 79506229110 + ... + 79506229127.

It is an arithmetic number, because the mean of its divisors is an integer number (344526992849).

Almost surely, 2^{1431112124133} is an apocalyptic number.

It is an amenable number.

1431112124133 is a deficient number, since it is larger than the sum of its proper divisors (636049832961).

1431112124133 is a wasteful number, since it uses less digits than its factorization.

1431112124133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159012458243 (or 159012458240 counting only the distinct ones).

The product of its digits is 1728, while the sum is 27.

Adding to 1431112124133 its reverse (3314212111341), we get a palindrome (4745324235474).

The spelling of 1431112124133 in words is "one trillion, four hundred thirty-one billion, one hundred twelve million, one hundred twenty-four thousand, one hundred thirty-three".