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14311121311 = 16567863833
BaseRepresentation
bin11010101010000001…
…00110000110011111
31100221100220021210001
431111000212012133
5213302121340221
610324024555131
71014433344514
oct152500460637
940840807701
1014311121311
116084289293
122934922aa7
131470c01a26
1499a94330b
1558b5dc391
hex35502619f

14311121311 has 4 divisors (see below), whose sum is σ = 14312001712. Its totient is φ = 14310240912.

The previous prime is 14311121303. The next prime is 14311121351. The reversal of 14311121311 is 11312111341.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11312111341 = 82871365043.

It is a cyclic number.

It is not a de Polignac number, because 14311121311 - 23 = 14311121303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14311121351) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 415350 + ... + 448483.

It is an arithmetic number, because the mean of its divisors is an integer number (3578000428).

Almost surely, 214311121311 is an apocalyptic number.

14311121311 is a deficient number, since it is larger than the sum of its proper divisors (880401).

14311121311 is an equidigital number, since it uses as much as digits as its factorization.

14311121311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 880400.

The product of its digits is 72, while the sum is 19.

Adding to 14311121311 its reverse (11312111341), we get a palindrome (25623232652).

The spelling of 14311121311 in words is "fourteen billion, three hundred eleven million, one hundred twenty-one thousand, three hundred eleven".

Divisors: 1 16567 863833 14311121311