Base | Representation |
---|---|
bin | 10100110100110101100… |
… | …001111110110111000001 |
3 | 12001210222100220212220020 |
4 | 110310311201332313001 |
5 | 141421414241211431 |
6 | 3013240511404053 |
7 | 205252354034613 |
oct | 24646541766701 |
9 | 5053870825806 |
10 | 1431122210241 |
11 | 501a321a64a9 |
12 | 1b143bb23629 |
13 | a4c536280a9 |
14 | 4d3a3ad4db3 |
15 | 2736055a696 |
hex | 14d3587edc1 |
1431122210241 has 8 divisors (see below), whose sum is σ = 1908199110144. Its totient is φ = 954063391920.
The previous prime is 1431122210213. The next prime is 1431122210299. The reversal of 1431122210241 is 1420122211341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1431122210241 - 214 = 1431122193857 is a prime.
It is a super-2 number, since 2×14311222102412 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1431122210341) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4334625 + ... + 4653086.
It is an arithmetic number, because the mean of its divisors is an integer number (238524888768).
Almost surely, 21431122210241 is an apocalyptic number.
It is an amenable number.
1431122210241 is a deficient number, since it is larger than the sum of its proper divisors (477076899903).
1431122210241 is an equidigital number, since it uses as much as digits as its factorization.
1431122210241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9040791.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 1431122210241 its reverse (1420122211341), we get a palindrome (2851244421582).
The spelling of 1431122210241 in words is "one trillion, four hundred thirty-one billion, one hundred twenty-two million, two hundred ten thousand, two hundred forty-one".
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