Search a number
-
+
14311222353 = 321797196331
BaseRepresentation
bin11010101010000001…
…11110110001010001
31100221101002102101100
431111000332301101
5213302133103403
610324031055013
71014434245221
oct152500766121
940841072340
1014311222353
11608434819a
122934971469
131470c38a0c
1499a96c081
1558b60c2a3
hex35503ec51

14311222353 has 24 divisors (see below), whose sum is σ = 21910520736. Its totient is φ = 8970249600.

The previous prime is 14311222333. The next prime is 14311222361. The reversal of 14311222353 is 35322211341.

14311222353 is a `hidden beast` number, since 1 + 431 + 1 + 2 + 223 + 5 + 3 = 666.

It is not a de Polignac number, because 14311222353 - 28 = 14311222097 is a prime.

It is a super-2 number, since 2×143112223532 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14311222333) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 100398 + ... + 196728.

It is an arithmetic number, because the mean of its divisors is an integer number (912938364).

Almost surely, 214311222353 is an apocalyptic number.

It is an amenable number.

14311222353 is a deficient number, since it is larger than the sum of its proper divisors (7599298383).

14311222353 is a wasteful number, since it uses less digits than its factorization.

14311222353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 97325 (or 97322 counting only the distinct ones).

The product of its digits is 4320, while the sum is 27.

Adding to 14311222353 its reverse (35322211341), we get a palindrome (49633433694).

The spelling of 14311222353 in words is "fourteen billion, three hundred eleven million, two hundred twenty-two thousand, three hundred fifty-three".

Divisors: 1 3 9 17 51 153 971 2913 8739 16507 49521 96331 148563 288993 866979 1637627 4912881 14738643 93537401 280612203 841836609 1590135817 4770407451 14311222353