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14311230107 = 43952816173
BaseRepresentation
bin11010101010000010…
…00000101010011011
31100221101002211000112
431111001000222123
5213302133330412
610324031154535
71014434306636
oct152501005233
940841084015
1014311230107
116084352aa9
122934975a4b
131470c3c3c5
1499a970c1d
1558b60e722
hex355040a9b

14311230107 has 8 divisors (see below), whose sum is σ = 14348869920. Its totient is φ = 14273614080.

The previous prime is 14311230067. The next prime is 14311230119. The reversal of 14311230107 is 70103211341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14311230107 - 218 = 14310967963 is a prime.

It is a super-2 number, since 2×143112301072 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14311230187) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2315273 + ... + 2321445.

It is an arithmetic number, because the mean of its divisors is an integer number (1793608740).

Almost surely, 214311230107 is an apocalyptic number.

14311230107 is a deficient number, since it is larger than the sum of its proper divisors (37639813).

14311230107 is an equidigital number, since it uses as much as digits as its factorization.

14311230107 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11893.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 14311230107 its reverse (70103211341), we get a palindrome (84414441448).

The spelling of 14311230107 in words is "fourteen billion, three hundred eleven million, two hundred thirty thousand, one hundred seven".

Divisors: 1 439 5281 6173 2318359 2709947 32599613 14311230107