1431131130221 has 4 divisors (see below), whose sum is σ = 1541218140252. Its totient is φ = 1321044120192.

The previous prime is 1431131130211. The next prime is 1431131130229. The reversal of 1431131130221 is 1220311311341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 588519122500 + 842612007721 = 767150^2 + 917939^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431131130221 - 2²⁶ = 1431064021357 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431131130229) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 55043504996 + ... + 55043505021.

It is an arithmetic number, because the mean of its divisors is an integer number (385304535063).

Almost surely, 2^{1431131130221} is an apocalyptic number.

It is an amenable number.

1431131130221 is a deficient number, since it is larger than the sum of its proper divisors (110087010031).

1431131130221 is a wasteful number, since it uses less digits than its factorization.

1431131130221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 110087010030.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 1431131130221 its reverse (1220311311341), we get a palindrome (2651442441562).

The spelling of 1431131130221 in words is "one trillion, four hundred thirty-one billion, one hundred thirty-one million, one hundred thirty thousand, two hundred twenty-one".