143113331141 has 4 divisors (see below), whose sum is σ = 156123633984. Its totient is φ = 130103028300.

The previous prime is 143113331113. The next prime is 143113331159. The reversal of 143113331141 is 141133311341.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 143113331141 - 2¹⁸ = 143113068997 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 143113331141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143113331341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6505151405 + ... + 6505151426.

It is an arithmetic number, because the mean of its divisors is an integer number (39030908496).

Almost surely, 2^143113331141 is an apocalyptic number.

143113331141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

143113331141 is a deficient number, since it is larger than the sum of its proper divisors (13010302843).

143113331141 is a wasteful number, since it uses less digits than its factorization.

143113331141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13010302842.

The product of its digits is 1296, while the sum is 26.

Adding to 143113331141 its reverse (141133311341), we get a palindrome (284246642482).

The spelling of 143113331141 in words is "one hundred forty-three billion, one hundred thirteen million, three hundred thirty-one thousand, one hundred forty-one".