1431140000221 has 4 divisors (see below), whose sum is σ = 1431239392444. Its totient is φ = 1431040608000.

The previous prime is 1431140000203. The next prime is 1431140000243. The reversal of 1431140000221 is 1220000411341.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1190250452196 + 240889548025 = 1090986^2 + 490805^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431140000221 - 2¹¹ = 1431139998173 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431140000261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 49674510 + ... + 49703311.

It is an arithmetic number, because the mean of its divisors is an integer number (357809848111).

Almost surely, 2^{1431140000221} is an apocalyptic number.

It is an amenable number.

1431140000221 is a deficient number, since it is larger than the sum of its proper divisors (99392223).

1431140000221 is an equidigital number, since it uses as much as digits as its factorization.

1431140000221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 99392222.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 1431140000221 its reverse (1220000411341), we get a palindrome (2651140411562).

The spelling of 1431140000221 in words is "one trillion, four hundred thirty-one billion, one hundred forty million, two hundred twenty-one", and thus it is an aban number.