1431200021341 has 4 divisors (see below), whose sum is σ = 1445370318684. Its totient is φ = 1417029724000.

The previous prime is 1431200021281. The next prime is 1431200021359.

1431200021341 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 626241153316 + 804958868025 = 791354^2 + 897195^2 .

It is a cyclic number.

It is not a de Polignac number, because 1431200021341 - 2⁷ = 1431200021213 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431200021441) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7085148520 + ... + 7085148721.

It is an arithmetic number, because the mean of its divisors is an integer number (361342579671).

Almost surely, 2^{1431200021341} is an apocalyptic number.

It is an amenable number.

1431200021341 is a deficient number, since it is larger than the sum of its proper divisors (14170297343).

1431200021341 is a wasteful number, since it uses less digits than its factorization.

1431200021341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14170297342.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 14312000 and 21341, that added together give a palindrome (14333341).

The spelling of 1431200021341 in words is "one trillion, four hundred thirty-one billion, two hundred million, twenty-one thousand, three hundred forty-one".