Base | Representation |
---|---|
bin | 100000100010101010111010… |
… | …110011100001000000110011 |
3 | 200202202010211021020020212011 |
4 | 200202222322303201000303 |
5 | 122224334312240212201 |
6 | 1224220234110143351 |
7 | 42101036604221320 |
oct | 4042527263410063 |
9 | 622663737206764 |
10 | 143120034304051 |
11 | 416699582621a2 |
12 | 14075755ab1b57 |
13 | 61b22135789cc |
14 | 274b091cd9b47 |
15 | 1182d31c10151 |
hex | 822abace1033 |
143120034304051 has 32 divisors (see below), whose sum is σ = 167134724928000. Its totient is φ = 120017560481280.
The previous prime is 143120034304043. The next prime is 143120034304087. The reversal of 143120034304051 is 150403430021341.
It is not a de Polignac number, because 143120034304051 - 23 = 143120034304043 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (143120034301051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3045537211 + ... + 3045584203.
It is an arithmetic number, because the mean of its divisors is an integer number (5222960154000).
Almost surely, 2143120034304051 is an apocalyptic number.
143120034304051 is a deficient number, since it is larger than the sum of its proper divisors (24014690623949).
143120034304051 is a wasteful number, since it uses less digits than its factorization.
143120034304051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82219.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 143120034304051 its reverse (150403430021341), we get a palindrome (293523464325392).
The spelling of 143120034304051 in words is "one hundred forty-three trillion, one hundred twenty billion, thirty-four million, three hundred four thousand, fifty-one".
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