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143120202231 = 347706734077
BaseRepresentation
bin1000010101001010100…
…0001111100111110111
3111200102021220120112210
42011102220033213313
54321102232432411
6145425402344503
713224436434546
oct2052250174767
9450367816483
10143120202231
1155773694276
12238a27bb133
131065b1414c6
146cd9ba415d
153ac9b0aca6
hex2152a0f9f7

143120202231 has 4 divisors (see below), whose sum is σ = 190826936312. Its totient is φ = 95413468152.

The previous prime is 143120202217. The next prime is 143120202307. The reversal of 143120202231 is 132202021341.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 143120202231 - 211 = 143120200183 is a prime.

It is a super-2 number, since 2×1431202022312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 143120202198 and 143120202207.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (143120202031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23853367036 + ... + 23853367041.

It is an arithmetic number, because the mean of its divisors is an integer number (47706734078).

Almost surely, 2143120202231 is an apocalyptic number.

143120202231 is a deficient number, since it is larger than the sum of its proper divisors (47706734081).

143120202231 is an equidigital number, since it uses as much as digits as its factorization.

143120202231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 47706734080.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 143120202231 its reverse (132202021341), we get a palindrome (275322223572).

The spelling of 143120202231 in words is "one hundred forty-three billion, one hundred twenty million, two hundred two thousand, two hundred thirty-one".

Divisors: 1 3 47706734077 143120202231