Base | Representation |
---|---|
bin | 11010101010001000… |
… | …11000010001100011 |
3 | 1100221102202200110120 |
4 | 31111010120101203 |
5 | 213302400111001 |
6 | 10324102131323 |
7 | 1014444645462 |
oct | 152504302143 |
9 | 40842680416 |
10 | 14312113251 |
11 | 60848a6577 |
12 | 2935120b43 |
13 | 147118b387 |
14 | 99ab209d9 |
15 | 58b736236 |
hex | 355118463 |
14312113251 has 4 divisors (see below), whose sum is σ = 19082817672. Its totient is φ = 9541408832.
The previous prime is 14312113247. The next prime is 14312113267. The reversal of 14312113251 is 15231121341.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14312113251 - 22 = 14312113247 is a prime.
It is not an unprimeable number, because it can be changed into a prime (14312111251) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2385352206 + ... + 2385352211.
It is an arithmetic number, because the mean of its divisors is an integer number (4770704418).
Almost surely, 214312113251 is an apocalyptic number.
14312113251 is a deficient number, since it is larger than the sum of its proper divisors (4770704421).
14312113251 is an equidigital number, since it uses as much as digits as its factorization.
14312113251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4770704420.
The product of its digits is 720, while the sum is 24.
Adding to 14312113251 its reverse (15231121341), we get a palindrome (29543234592).
The spelling of 14312113251 in words is "fourteen billion, three hundred twelve million, one hundred thirteen thousand, two hundred fifty-one".
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