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1431212103 = 32159023567
BaseRepresentation
bin101010101001110…
…1001000001000111
310200202002002220200
41111103221001013
510412342241403
6354003501543
750316050016
oct12523510107
93622062820
101431212103
11674977922
1233b3878b3
1319a689389
14d8118a7d
15859acca3
hex554e9047

1431212103 has 6 divisors (see below), whose sum is σ = 2067306384. Its totient is φ = 954141396.

The previous prime is 1431212093. The next prime is 1431212131. The reversal of 1431212103 is 3012121341.

1431212103 is a `hidden beast` number, since 1 + 431 + 21 + 210 + 3 = 666.

It is not a de Polignac number, because 1431212103 - 212 = 1431208007 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1431212603) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 79511775 + ... + 79511792.

It is an arithmetic number, because the mean of its divisors is an integer number (344551064).

Almost surely, 21431212103 is an apocalyptic number.

1431212103 is a deficient number, since it is larger than the sum of its proper divisors (636094281).

1431212103 is a wasteful number, since it uses less digits than its factorization.

1431212103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 159023573 (or 159023570 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

The square root of 1431212103 is about 37831.3640118883. The cubic root of 1431212103 is about 1126.9413992305.

Adding to 1431212103 its reverse (3012121341), we get a palindrome (4443333444).

The spelling of 1431212103 in words is "one billion, four hundred thirty-one million, two hundred twelve thousand, one hundred three".

Divisors: 1 3 9 159023567 477070701 1431212103