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14312123443003 = 35939866639117
BaseRepresentation
bin1101000001000100110100…
…0010001010011100111011
31212200020002111020200211011
43100101031002022130323
53333442212100134003
650234522043414351
73005005522011001
oct320211502123473
955606074220734
1014312123443003
114618812627071
1217319512243b7
137ca820678469
143769d3762a71
1519c457ab346d
hexd044d08a73b

14312123443003 has 4 divisors (see below), whose sum is σ = 14351990082480. Its totient is φ = 14272256803528.

The previous prime is 14312123442983. The next prime is 14312123443021. The reversal of 14312123443003 is 30034432121341.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14312123443003 - 217 = 14312123311931 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14312123443603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19933319200 + ... + 19933319917.

It is an arithmetic number, because the mean of its divisors is an integer number (3587997520620).

Almost surely, 214312123443003 is an apocalyptic number.

14312123443003 is a deficient number, since it is larger than the sum of its proper divisors (39866639477).

14312123443003 is an equidigital number, since it uses as much as digits as its factorization.

14312123443003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39866639476.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 14312123443003 its reverse (30034432121341), we get a palindrome (44346555564344).

The spelling of 14312123443003 in words is "fourteen trillion, three hundred twelve billion, one hundred twenty-three million, four hundred forty-three thousand, three".

Divisors: 1 359 39866639117 14312123443003