Base | Representation |
---|---|
bin | 1101000001000100110100… |
… | …0010001010100110010011 |
3 | 1212200020002111020201122101 |
4 | 3100101031002022212103 |
5 | 3333442212100143403 |
6 | 50234522043421231 |
7 | 3005005522012516 |
oct | 320211502124623 |
9 | 55606074221571 |
10 | 14312123443603 |
11 | 4618812627567 |
12 | 1731951224817 |
13 | 7ca82067880b |
14 | 3769d3762d7d |
15 | 19c457ab371d |
hex | d044d08a993 |
14312123443603 has 2 divisors, whose sum is σ = 14312123443604. Its totient is φ = 14312123443602.
The previous prime is 14312123443589. The next prime is 14312123443643. The reversal of 14312123443603 is 30634432121341.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14312123443603 - 233 = 14303533509011 is a prime.
It is not a weakly prime, because it can be changed into another prime (14312123443643) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7156061721801 + 7156061721802.
It is an arithmetic number, because the mean of its divisors is an integer number (7156061721802).
Almost surely, 214312123443603 is an apocalyptic number.
14312123443603 is a deficient number, since it is larger than the sum of its proper divisors (1).
14312123443603 is an equidigital number, since it uses as much as digits as its factorization.
14312123443603 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 124416, while the sum is 37.
Adding to 14312123443603 its reverse (30634432121341), we get a palindrome (44946555564944).
The spelling of 14312123443603 in words is "fourteen trillion, three hundred twelve billion, one hundred twenty-three million, four hundred forty-three thousand, six hundred three".
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