Search a number
-
+
1431212420000 = 255411411011571
BaseRepresentation
bin10100110100111010111…
…010000110101110100000
312001211012122200000102102
4110310322322012232200
5141422110334420000
63013253453105532
7205254530563046
oct24647272065640
95054178600372
101431212420000
11501a79110420
121b14661882a8
13a4c6922164c
144d3b1a98396
15273684293d5
hex14d3ae86ba0

1431212420000 has 480 divisors, whose sum is σ = 3976260539328. Its totient is φ = 502400000000.

The previous prime is 1431212419991. The next prime is 1431212420051. The reversal of 1431212420000 is 242121341.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 911019215 + ... + 911020785.

Almost surely, 21431212420000 is an apocalyptic number.

1431212420000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1431212420000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1988130269664).

1431212420000 is an abundant number, since it is smaller than the sum of its proper divisors (2545048119328).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1431212420000 is a wasteful number, since it uses less digits than its factorization.

1431212420000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1754 (or 1731 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1431212420000 its reverse (242121341), we get a palindrome (1431454541341).

The spelling of 1431212420000 in words is "one trillion, four hundred thirty-one billion, two hundred twelve million, four hundred twenty thousand".