Base | Representation |
---|---|
bin | 1000010101001010110… |
… | …0001101110001010111 |
3 | 111200102100212110112001 |
4 | 2011102230031301113 |
5 | 4321103014240343 |
6 | 145425440540131 |
7 | 13224451331530 |
oct | 2052254156127 |
9 | 450370773461 |
10 | 143121243223 |
11 | 557742353a2 |
12 | 238a3021647 |
13 | 1065b41728a |
14 | 6cd9d95687 |
15 | 3ac9c6444d |
hex | 2152b0dc57 |
143121243223 has 8 divisors (see below), whose sum is σ = 163576623392. Its totient is φ = 122668235136.
The previous prime is 143121243191. The next prime is 143121243263. The reversal of 143121243223 is 322342121341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 143121243223 - 25 = 143121243191 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 143121243191 and 143121243200.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (143121243263) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 461790 + ... + 706747.
It is an arithmetic number, because the mean of its divisors is an integer number (20447077924).
Almost surely, 2143121243223 is an apocalyptic number.
143121243223 is a deficient number, since it is larger than the sum of its proper divisors (20455380169).
143121243223 is a wasteful number, since it uses less digits than its factorization.
143121243223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1186041.
The product of its digits is 6912, while the sum is 28.
Adding to 143121243223 its reverse (322342121341), we get a palindrome (465463364564).
The spelling of 143121243223 in words is "one hundred forty-three billion, one hundred twenty-one million, two hundred forty-three thousand, two hundred twenty-three".
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