Base | Representation |
---|---|
bin | 11010101010001001… |
… | …01101111100100111 |
3 | 1100221102221012020102 |
4 | 31111010231330213 |
5 | 213302410431043 |
6 | 10324104054315 |
7 | 1014445465340 |
oct | 152504557447 |
9 | 40842835212 |
10 | 14312202023 |
11 | 6084957239 |
12 | 293516439b |
13 | 14711bc8c2 |
14 | 99ab450c7 |
15 | 58b7526b8 |
hex | 35512df27 |
14312202023 has 8 divisors (see below), whose sum is σ = 16368024960. Its totient is φ = 12259184760.
The previous prime is 14312202017. The next prime is 14312202041. The reversal of 14312202023 is 32020221341.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14312202023 - 24 = 14312202007 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14312201986 and 14312202004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14312202623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 690473 + ... + 710898.
It is an arithmetic number, because the mean of its divisors is an integer number (2046003120).
Almost surely, 214312202023 is an apocalyptic number.
14312202023 is a deficient number, since it is larger than the sum of its proper divisors (2055822937).
14312202023 is a wasteful number, since it uses less digits than its factorization.
14312202023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1402837.
The product of its (nonzero) digits is 576, while the sum is 20.
Adding to 14312202023 its reverse (32020221341), we get a palindrome (46332423364).
The spelling of 14312202023 in words is "fourteen billion, three hundred twelve million, two hundred two thousand, twenty-three".
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