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143122034105 = 5231244539427
BaseRepresentation
bin1000010101001010111…
…1001110110110111001
3111200102102100122101222
42011102233032312321
54321103220042410
6145425505521425
713224461134361
oct2052257166671
9450372318358
10143122034105
1155774725616
12238a3343275
131065b63325b
146cda11d9a1
153ac9d6d955
hex2152bcedb9

143122034105 has 8 divisors (see below), whose sum is σ = 179213677632. Its totient is φ = 109519469488.

The previous prime is 143122034101. The next prime is 143122034113. The reversal of 143122034105 is 501430221341.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 143122034105 - 22 = 143122034101 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (143122034101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 622269599 + ... + 622269828.

It is an arithmetic number, because the mean of its divisors is an integer number (22401709704).

Almost surely, 2143122034105 is an apocalyptic number.

It is an amenable number.

143122034105 is a deficient number, since it is larger than the sum of its proper divisors (36091643527).

143122034105 is a wasteful number, since it uses less digits than its factorization.

143122034105 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1244539455.

The product of its (nonzero) digits is 2880, while the sum is 26.

Adding to 143122034105 its reverse (501430221341), we get a palindrome (644552255446).

The spelling of 143122034105 in words is "one hundred forty-three billion, one hundred twenty-two million, thirty-four thousand, one hundred five".

Divisors: 1 5 23 115 1244539427 6222697135 28624406821 143122034105